flubby

flubbyflubby Posts: 50Player
in R&R
I used to play this game, but gave it up to play csgo. Wanna do an AMA? Fire away...

Comments

  • FlatlanderFlatlander Posts: 623Player
    If Log x (1 / 8) = - 3 / 2, then x is equal to ?
    AAPG is good!
  • Dct.F|LeventeDct.F|Levente Posts: 509Beta Tester
    Flatlander wrote: »
    If Log x (1 / 8) = - 3 / 2, then x is equal to ?

    Syntax ambiguous, cannot solve. Is it Log(x)*1/8? Log(x*1/8)?
    Theory and reality are not that different. In theory.
  • FlatlanderFlatlander Posts: 623Player
    Rewrite the logarithmic equations using exponential equation

    x- 3 / 2 = 1 / 8

    The above equation may be rewritten as

    x - 3 / 2 = 1 / 23 = 2-3

    (√x)-3 = 2-3

    The above equation gives

    √x = 2 or x = 4

    :D
    AAPG is good!
  • Dct.F|LeventeDct.F|Levente Posts: 509Beta Tester
    You are either using syntax I don't know or incorrect syntax. Or bad copy-pasting. (Most likely the latter.)

    You are missing the power symbols and some brackets for sure.
    Theory and reality are not that different. In theory.
  • FlatlanderFlatlander Posts: 623Player
    Some day someone will use it to calculate the transport of a person from one ship to another at warp 7.2.
    AAPG is good!
  • flubbyflubby Posts: 50Player
    nerds!
  • doogle!doogle! Posts: 648Player
    when are my in-laws leaving my house..
  • frankoffrankof Posts: 998Moderator
    45s after they come up in the morning finding you naked in front of the tv watching horror-gore movies, drunk. and armed...
    ss_4_frankof.png
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